面试真题
快手
2.用户中两人一定认识的组合数

快手大数据面试SQL-用户中两人一定认识的组合数

一、题目

有某城市网吧上网记录表,包含字段:网吧id,访客id(身份证号),上线时间,下线时间。

  • 规则1:如果两个用户在同一个网吧上线时间或者下线时间间隔在10分钟以内,则两个用户可能认识;
  • 规则2:如果两个用户在三家以上的网吧出现过【规则1】可能认识的情况,则两人一定认识;

请计算该市中两人一定认识的组合数

+---------+----------+----------------------+----------------------+
| bar_id  | user_id  |      login_time      |     logoff_time      |
+---------+----------+----------------------+----------------------+
| 1       | 001      | 2023-08-01 09:00:00  | 2023-08-01 10:00:00  |
| 1       | 003      | 2023-08-01 09:04:00  | 2023-08-01 11:00:00  |
| 2       | 004      | 2023-08-01 10:00:00  | 2023-08-01 12:02:00  |
| 1       | 006      | 2023-08-01 10:00:00  | 2023-08-01 12:00:00  |
| 2       | 005      | 2023-08-01 10:10:00  | 2023-08-01 11:00:00  |
| 2       | 001      | 2023-08-01 11:01:00  | 2023-08-01 12:00:00  |
| 2       | 002      | 2023-08-01 11:03:00  | 2023-08-01 14:00:00  |
| 3       | 002      | 2023-08-02 15:00:00  | 2023-08-02 17:06:00  |
| 3       | 001      | 2023-08-02 16:01:00  | 2023-08-02 17:07:00  |
| 3       | 004      | 2023-08-02 16:02:00  | 2023-08-02 18:00:00  |
| 3       | 003      | 2023-08-02 20:00:00  | 2023-08-02 22:00:00  |
| 4       | 001      | 2023-08-03 17:00:00  | 2023-08-03 19:00:00  |
| 4       | 002      | 2023-08-03 18:00:00  | 2023-08-03 21:00:00  |
| 4       | 003      | 2023-08-03 18:05:00  | 2023-08-03 22:00:00  |
| 4       | 004      | 2023-08-03 19:00:00  | 2023-08-03 18:58:00  |
+---------+----------+----------------------+----------------------+

二、分析

  1. 首先计算可能认识的人,由于所有可能认识的条件必须发生在同一个网吧内,以bar_id进行自关联,然后id要求t1>t2来保证同一个用户和其他的用户只进行一次关联,限定上线时间或者下线时间在10分钟内;
  2. 计算出可能认识的用户组中,出现的网吧个数;
  3. 计算网吧个数>=3的组合数;
维度评分
题目难度⭐️⭐️⭐️
题目清晰度⭐️⭐️⭐️⭐️⭐️
业务常见度⭐️⭐️⭐️

三、SQL

1.可能认识的记录

查询SQL

select t1.bar_id,
       t1.user_id,
       t1.login_time,
       t1.logoff_time,
       t2.bar_id,
       t2.user_id,
       t2.login_time,
       t2.logoff_time
from (select bar_id, user_id, login_time, logoff_time
      from t2_netbar) t1
         join
     (select bar_id, user_id, login_time, logoff_time
      from t2_netbar) t2
     on t1.bar_id = t2.bar_id
where t1.user_id < t2.user_id --限定t1的user_id <t2的user_id,防止重复关联和自关联
  and (
    abs(unix_timestamp(t1.login_time, 'yyyy-MM-dd HH:mm:ss') - unix_timestamp(t2.login_time, 'yyyy-MM-dd HH:mm:ss')) <
    600-- 上线时间在10min内
        or
    abs(unix_timestamp(t1.logoff_time, 'yyyy-MM-dd HH:mm:ss') - unix_timestamp(t2.logoff_time, 'yyyy-MM-dd HH:mm:ss')) <
    600 -- 下线时间在10min内
    )

查询结果

+------------+-------------+----------------------+----------------------+------------+-------------+----------------------+----------------------+
| t1.bar_id  | t1.user_id  |    t1.login_time     |    t1.logoff_time    | t2.bar_id  | t2.user_id  |    t2.login_time     |    t2.logoff_time    |
+------------+-------------+----------------------+----------------------+------------+-------------+----------------------+----------------------+
| 2          | 001         | 2023-08-01 11:01:00  | 2023-08-01 12:00:00  | 2          | 002         | 2023-08-01 11:03:00  | 2023-08-01 14:00:00  |
| 3          | 001         | 2023-08-02 16:01:00  | 2023-08-02 17:07:00  | 3          | 002         | 2023-08-02 15:00:00  | 2023-08-02 17:06:00  |
| 1          | 001         | 2023-08-01 09:00:00  | 2023-08-01 10:00:00  | 1          | 003         | 2023-08-01 09:04:00  | 2023-08-01 11:00:00  |
| 4          | 002         | 2023-08-03 18:00:00  | 2023-08-03 21:00:00  | 4          | 003         | 2023-08-03 18:05:00  | 2023-08-03 22:00:00  |
| 2          | 001         | 2023-08-01 11:01:00  | 2023-08-01 12:00:00  | 2          | 004         | 2023-08-01 10:00:00  | 2023-08-01 12:02:00  |
| 3          | 001         | 2023-08-02 16:01:00  | 2023-08-02 17:07:00  | 3          | 004         | 2023-08-02 16:02:00  | 2023-08-02 18:00:00  |
| 4          | 001         | 2023-08-03 17:00:00  | 2023-08-03 19:00:00  | 4          | 004         | 2023-08-03 19:00:00  | 2023-08-03 18:58:00  |
+------------+-------------+----------------------+----------------------+------------+-------------+----------------------+----------------------+

2.按照t1的user_id、t2的user_id 进行分组,统计网吧ID个数

执行SQL

select user_id1,
       user_id2,
       count(distinct bar_id) as bar_num
from (select t1.bar_id,
             t1.user_id as user_id1,
             t2.user_id as user_id2
      from (select bar_id, user_id, login_time, logoff_time
            from t2_netbar) t1
               join
           (select bar_id, user_id, login_time, logoff_time
            from t2_netbar) t2
           on t1.bar_id = t2.bar_id
      where t1.user_id < t2.user_id --限定t1的user_id <t2的user_id,防止重复关联和自关联
        and (
          abs(unix_timestamp(t1.login_time, 'yyyy-MM-dd HH:mm:ss') -
              unix_timestamp(t2.login_time, 'yyyy-MM-dd HH:mm:ss')) < 600-- 上线时间在10min内
              or
          abs(unix_timestamp(t1.logoff_time, 'yyyy-MM-dd HH:mm:ss') -
              unix_timestamp(t2.logoff_time, 'yyyy-MM-dd HH:mm:ss')) < 600 -- 下线时间在10min内
          )) t
group by user_id1, user_id2

查询结果

+-----------+-----------+----------+
| user_id1  | user_id2  | bar_num  |
+-----------+-----------+----------+
| 001       | 002       | 2        |
| 001       | 003       | 1        |
| 001       | 004       | 3        |
| 002       | 003       | 1        |
+-----------+-----------+----------+

3.统计最终结果

执行SQL

select count(1) as group_nums
from (select user_id1,
             user_id2,
             count(distinct bar_id) as bar_num
      from (select t1.bar_id,
                   t1.user_id as user_id1,
                   t2.user_id as user_id2
            from (select bar_id, user_id, login_time, logoff_time
                  from t2_netbar) t1
                     join
                 (select bar_id, user_id, login_time, logoff_time
                  from t2_netbar) t2
                 on t1.bar_id = t2.bar_id
            where t1.user_id < t2.user_id --限定t1的user_id <t2的user_id,防止重复关联和自关联
              and (
                abs(unix_timestamp(t1.login_time, 'yyyy-MM-dd HH:mm:ss') -
                    unix_timestamp(t2.login_time, 'yyyy-MM-dd HH:mm:ss')) < 600-- 上线时间在10min内
                    or
                abs(unix_timestamp(t1.logoff_time, 'yyyy-MM-dd HH:mm:ss') -
                    unix_timestamp(t2.logoff_time, 'yyyy-MM-dd HH:mm:ss')) < 600 -- 下线时间在10min内
                )) t
      group by user_id1, user_id2) tt
where bar_num >= 3

查询结果

+-------------+
| group_nums  |
+-------------+
| 1           |
+-------------+

四、建表语句和数据插入

--建表语句
CREATE TABLE t2_netbar (
bar_id bigint COMMENT '网吧ID',
user_id string COMMENT '用户ID',
login_time string COMMENT '上线时间',
logoff_time string COMMENT '下线时间'
) COMMENT '网吧上下线记录表';
-- 插入数据
insert into t2_netbar(bar_id,user_id,login_time,logoff_time)
values
(1,'001','2023-08-01 09:00:00','2023-08-01 10:00:00'),
(2,'001','2023-08-01 11:01:00','2023-08-01 12:00:00'),
(2,'002','2023-08-01 11:03:00','2023-08-01 14:00:00'),
(3,'001','2023-08-02 16:01:00','2023-08-02 17:07:00'),
(3,'002','2023-08-02 15:00:00','2023-08-02 17:06:00'),
(4,'001','2023-08-03 17:00:00','2023-08-03 19:00:00'),
(4,'002','2023-08-03 18:00:00','2023-08-03 21:00:00'),
(1,'003','2023-08-01 09:04:00','2023-08-01 11:00:00'),
(3,'003','2023-08-02 20:00:00','2023-08-02 22:00:00'),
(4,'003','2023-08-03 18:05:00','2023-08-03 22:00:00'),
(2,'004','2023-08-01 10:00:00','2023-08-01 12:02:00'),
(3,'004','2023-08-02 16:02:00','2023-08-02 18:00:00'),
(4,'004','2023-08-03 19:00:00','2023-08-03 18:58:00'),
(2,'005','2023-08-01 10:10:00','2023-08-01 11:00:00'),
(1,'006','2023-08-01 10:00:00','2023-08-01 12:00:00')

本文同步在微信公众号”数据仓库技术“和个人博客”数据仓库技术 (opens in a new tab)“发表;